A) 7
B) 8
C) 9
D) None of these
Correct Answer: C
Solution :
\[\frac{1}{6}=\frac{^{n}{{C}_{6}}{{({{2}^{1/3}})}^{n-6}}{{({{3}^{-1/3}})}^{6}}}{^{n}{{C}_{n-6}}{{({{2}^{1/3}})}^{6}}{{({{3}^{-1/3}})}^{n-6}}}\]or \[{{6}^{-1}}={{6}^{-4}}{{.6}^{n/3}}={{6}^{n/3-4}}\] \\[\frac{n}{3}-4=-1\] \[\Rightarrow \] n = 9.You need to login to perform this action.
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