A) -1680
B) 1680
C) 3360
D) 6720
Correct Answer: C
Solution :
The coefficient of \[{{x}^{16}}\]in the expansion of \[{{({{x}^{2}}-2x)}^{10}}\] = The coefficient of \[{{x}^{16}}\]in \[{{x}^{10}}{{(x-2)}^{10}}\] = The coefficient of \[{{x}^{6}}\]in \[{{(x-2)}^{10}}\] = \[^{10}{{C}_{4}}{{.2}^{4}},\,\,\,\,\left( \because \,\,{{T}_{r+1}}={{\,}^{n}}{{C}_{r}}{{x}^{n-r}}{{a}^{r}} \right)\] \[=210\times 16=3360\].You need to login to perform this action.
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