A) - 7930
B) - 495
C) 495
D) 7920
Correct Answer: D
Solution :
We have \[{{(x)}^{12-r}}{{\left( \frac{1}{{{x}^{2}}} \right)}^{r}}={{x}^{0}}\,\,\Rightarrow {{x}^{12-3r}}={{x}^{0}}\Rightarrow r=4\] Hence the required term is \[^{12}{{C}_{4}}{{2}^{8}}{{\left( -\frac{1}{2} \right)}^{4}}=7920\].You need to login to perform this action.
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