A) 10
B) 12
C) 14
D) None of these
Correct Answer: B
Solution :
Since n is even therefore \[{{\left( \frac{n}{2}+1 \right)}^{th}}\] term is middle term, hence \[^{n}{{C}_{n/2}}{{({{x}^{2}})}^{n/2}}{{\left( \frac{1}{x} \right)}^{n/2}}=924{{x}^{6}}\] \[\Rightarrow \] \[{{x}^{n/2}}={{x}^{6}}\Rightarrow n=12\].You need to login to perform this action.
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