A) 153090
B) 150000
C) 150090
D) 153180
Correct Answer: A
Solution :
\[{{T}_{r+1}}={}^{10}{{C}_{r}}{{({{x}^{2}})}^{10-r}}{{\left( \frac{-3\sqrt{3}}{{{x}^{3}}} \right)}^{r}}\] For term independent of x, \[20-2r-3r=0\Rightarrow r=4\] \ \[{{T}_{4+1}}={}^{10}{{C}_{4}}{{(-3)}^{4}}{{(\sqrt{3})}^{4}}=153090.\]You need to login to perform this action.
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