A) \[\frac{1.3.5....(2n-3)}{n!}\]
B) \[\frac{1.3.5....(2n-1)}{n!}\]
C) \[\frac{1.3.5....(2n+1)}{n!}\]
D) None of these
Correct Answer: B
Solution :
Obviously the middle term \[={{\,}^{2n}}{{C}_{n}}{{(x)}^{n}}.{{\left( \frac{1}{2x} \right)}^{n}}\]\[=\frac{2n!}{n!.n!{{.2}^{n}}}=\frac{1.3.5....(2n-1)}{n!}\].You need to login to perform this action.
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