A) 0
B) 2
C) 7
D) 17
Correct Answer: B
Solution :
The two circles are \[{{C}_{1}}(0,\,0),\,{{r}_{1}}=12\], \[{{C}_{2}}(3,\,4),\,{{r}_{2}}=5\] and it passes through origin, the centre of \[{{C}_{1}}\]. \[{{C}_{1}}{{C}_{2}}=5<{{r}_{1}}-{{r}_{2}}=7\] Hence circle \[{{C}_{2}}\]lies inside circle\[{{C}_{1}}\]. Therefore minimum distance between them is \[AB={{C}_{1}}B-{{C}_{1}}A={{r}_{1}}-2{{r}_{2}}=12-10=2.\]You need to login to perform this action.
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