A) \[{{z}_{1}}^{2}+{{z}_{2}}^{2}+{{z}_{3}}^{2}={{z}_{1}}{{z}_{2}}{{z}_{3}}\]
B) \[{{({{z}_{3}}-{{z}_{1}})}^{2}}={{z}_{3}}-{{z}_{2}}\]
C) \[{{({{z}_{1}}-{{z}_{2}})}^{2}}=({{z}_{1}}-{{z}_{3}})\,({{z}_{3}}-{{z}_{2}})\]
D) \[{{({{z}_{1}}-{{z}_{2}})}^{2}}=2({{z}_{1}}-{{z}_{3}})\,({{z}_{3}}-{{z}_{2}})\]
Correct Answer: D
Solution :
\[BC=AC\] and \[\angle C=\pi /2\] By rotation about \[C\] in anti-clockwise sense \[CB=CA\,{{e}^{i\,\pi /2}}\]You need to login to perform this action.
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