A) Parallelogram
B) Rectangle
C) Square
D) Rhombus
Correct Answer: C
Solution :
Given the vertices of quadrilateral \[A(1+2i),B(-3+i),C(-2-3i)\]and \[D(2-2i)\] Now, \[AB=\sqrt{16+1}=\sqrt{17},BC=\sqrt{16+1}=\sqrt{17}\] \[CD=\sqrt{16+1}=\sqrt{17,}\,DA=\sqrt{16+1}=\sqrt{17}\] \[AC=\sqrt{9+25}=\sqrt{34},\,BD=\sqrt{25+9}=\sqrt{34}\] Hence it is a square.You need to login to perform this action.
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