A) \[|z|=5\]
B) \[|z|<5\]
C) \[|z|>5\]
D) None of these
Correct Answer: B
Solution :
We have \[{{\log }_{\sqrt{3}}}\left( \frac{|z{{|}^{2}}-|z|+1}{2+|z|} \right)<2\] Þ \[\frac{|z{{|}^{2}}-|z|+1}{2+|z|}<{{(\sqrt{3})}^{2}}\] Þ \[|z{{|}^{2}}-4|z|-5<0\] Þ \[-1<|z|<5\] Þ \[|z|<5\]as \[|z|>0\] \ Locus of \[z\] is |z|<5You need to login to perform this action.
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