A) 13cm
B) 8cm
C) 5cm
D) 7cm
Correct Answer: A
Solution :
AP = 12cm and CQ=5cm. AB = 24 cm and CD= 10 cm. Since, the perpendicular to the chord bisects the chord. In \[\angle BDC={{25}^{o}}\] In \[\angle BDC\] Subtracting, we have, \[{{85}^{o}}\] \[{{120}^{o}}\] \[{{115}^{o}}\] \[{{95}^{o}}\] or \[\angle PAD={{30}^{o}}\] \[\angle CPA={{45}^{o}}\] or \[\angle CBP\] or \[{{105}^{o}}\] or \[{{115}^{o}}\]. \[{{135}^{o}}\] or \[\Delta ABC\], i.e., Radius = 13cm.You need to login to perform this action.
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