A) 3:5
B) 9:16
C) 6:9
D) None of these
Correct Answer: B
Solution :
First draw \[{{54}^{o}}\] Given: \[{{27}^{o}}\] Let DE = 3x, BC = 5x And \[{{90}^{o}}\] Now, Area of \[\angle BOD={{120}^{o}}\] Area of \[\angle ACD\] Now, Area of trapezium DEBC = Area of \[{{30}^{o}}\] of\[{{40}^{o}}\] \[{{60}^{o}}\] Ratio of area of \[{{90}^{o}}\] and Area of trapezium \[{{30}^{o}}\]You need to login to perform this action.
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