A) \[85{}^\circ \]
B) \[95{}^\circ \]
C) \[70{}^\circ \]
D) \[115{}^\circ \]
Correct Answer: B
Solution :
Since, APQD is a cyclic quadrilateral, therefore \[\angle A+\angle DQP={{180}^{o}}\] or \[\angle DQP={{180}^{o}}-{{85}^{o}}={{95}^{o}}\] or \[\angle PQC={{180}^{o}}-\angle DQP={{85}^{o}}\] \[\therefore \] \[\angle B={{180}^{o}}-85=95\]
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