A) BC < CA < CD
B) BC > CA > CD
C) BC < CA, CA > CD
D) BC > CA, CA < CD
Correct Answer: A
Solution :
Here \[\angle B=\angle C={{65}^{o}}\]and \[\angle D={{30}^{o}}\] From the triangle ABD \[\therefore \] \[\angle A={{85}^{o}}\] In triangle ABC \[\angle A={{50}^{o}}\] \[BC<CA\] In triangle ACD \[\angle A={{85}^{o}}-{{50}^{o}}={{35}^{o}}\] \[\therefore \] \[CD>CD\]You need to login to perform this action.
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