A) \[30{}^\circ \]
B) \[35{}^\circ \]
C) \[40{}^\circ \]
D) Cannot be determined
Correct Answer: C
Solution :
Referring figure. \[\angle DFB=\angle ECB={{70}^{o}}\] \[\angle AFA={{180}^{o}}-{{70}^{o}}={{110}^{o}}\] Hence, from \[\Delta \,AFB,\] \[\angle DAB=\angle FAB\] \[={{180}^{o}}-({{30}^{o}}+\angle AFB)\] \[={{180}^{o}}-({{30}^{o}}+{{110}^{o}})\] \[={{40}^{o}}\]
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