9th Class Mathematics Geometry Question Bank Geometry

  • question_answer
    In the following figure, \[AE\bot BC,\,\,D\] is the mid-point of BC, then \[x\] is equal to

    A) \[\frac{1}{\alpha }\left[ {{b}^{2}}-{{d}^{2}}-\frac{{{a}^{2}}}{4} \right]\]

    B) \[\frac{h+d}{3}\]

    C) \[\frac{c+d-h}{2}\]

    D) \[\frac{{{a}^{2}}+{{b}^{2}}+{{d}^{2}}-{{c}^{2}}}{4}\]

    Correct Answer: A

    Solution :

     Not available


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