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9th Class Mathematics Geometry Question Bank Geometry

  • question_answer
    In the given figure, \[\angle \,\text{B}\,\text{=}\angle \,\text{C}\,=\,65{}^\circ \] and \[\angle \,D\,=\,30{}^\circ \]. Then.

    A) BC < CA < CD

    B) BC > CA > CD

    C) BC < CA, CA > CD

    D) BC > CA, CA < CD

    Correct Answer: A

    Solution :

     Here \[\angle B=\angle C={{65}^{o}}\]and \[\angle D={{30}^{o}}\] From the triangle ABD \[\therefore \]                  \[\angle A={{85}^{o}}\] In triangle ABC   \[\angle A={{50}^{o}}\]                                 \[BC<CA\] In triangle ACD   \[\angle A={{85}^{o}}-{{50}^{o}}={{35}^{o}}\] \[\therefore \]  \[CD>CD\]


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