A) \[\frac{1}{4}\,AK\]
B) \[\frac{1}{2}\,AK\]
C) \[\frac{1}{3}\,AK\]
D) \[\frac{2}{3}\,AK\]
Correct Answer: B
Solution :
Since angles BXO and CXK are similar. \[\therefore \] \[\frac{OX}{XK}=\frac{BX}{OX}=1\] \[\Rightarrow \] \[OX=XK\] Also> \[\frac{AO}{XK}=\frac{AO}{OX}=\frac{2}{1}\] \[\Rightarrow \] \[AO=OK\] Hence, \[AK=2AO\] \[\Rightarrow \] \[AO=\frac{1}{2}AK\]You need to login to perform this action.
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