A) Equilateral
B) Isosceles
C) Right angled
D) Scalene
E) None of these
Correct Answer: B
Solution :
Explanation In ABDC and ABEC, \[\operatorname{BC} = BC\] (common) \[\angle BDC=\angle BEC\] (each equal to 90°) \[\operatorname{BD}=CE\] (Given) \[\therefore \,\,\,\Delta BDC\cong \Delta BEC\] \[\angle DCB\,\,=\,\,\angle EBC\] (By c.p.c.t) \[\Rightarrow \,\,\,\, AB = AC\] (Sides opposite to equal adjacent angles in a triangle) Hence, the \[\Delta ABC\] is an isosceles triangle.You need to login to perform this action.
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