A) (AD 4- BE + CF) = (AB + BC + CD)
B) (AD + BE + CD) > -3 (AB + BC + CA)
C) (AD + BE + CF) < 3- (AB + BC + CA)
D) (AD + BE + CF) = - (AB + BC + CA)
Correct Answer: B
Solution :
From \[\Delta \,BCG,\] \[BG+GC>BC\] or \[\frac{2}{3}BE+\frac{2}{3}CF>BC\] or \[BE+CF>\frac{3}{2}BC\] ??.(i) Similarly, \[CF+AD>\frac{3}{2}CA\] ??.(ii) and \[AD+BE>\frac{3}{2}AB\] ??(iii) Adding equations (i), (ii) and (Hi), we get \[2(AD+BE+CF)>\frac{3}{2}(AB+BC+CA)\] or \[AD+BE+CF>\frac{3}{4}(AB+BC+CA)\]You need to login to perform this action.
You will be redirected in
3 sec