A) \[2\sqrt{3}\,cm\]
B) \[4\sqrt{3}\,cm\]
C) \[4\sqrt{2}\,cm\]
D) \[8 cm\]
Correct Answer: B
Solution :
If O and O' be the centres, then OO' will be the common radius. \[\therefore \] \[OO'=4\,cm\] \[\therefore \] \[OA=PB=O'A\] \[=O'B\] (because these are radii) \[\therefore \] \[OAO'B\] is a rhombus. But the diagonals of a rhombus intersect each other at right angle. \[\therefore \] \[\angle AEO={{90}^{o}}\] \[\therefore \] \[A{{E}^{2}}+O{{E}^{2}}=A{{O}^{2}}\] or \[A{{E}^{2}}+4=16\] \[AE=\sqrt{12}\] \[=2\sqrt{3}\] \[\therefore \] \[AB=2\times 2\sqrt{3}\] \[=4\sqrt{3}\]You need to login to perform this action.
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