A) 5, 5
B) 6, 4
C) 7,3
D) 8,2
Correct Answer: B
Solution :
(i) All the four sides of a rhombus are equal (ii) Diagonals of a rhombus are mutually perpendicular and bisect each other \[\therefore \] \[4a=4\sqrt{13}\] \[\Rightarrow \] \[a=\sqrt{13}\] and \[2x+2y=10\] \[\Rightarrow \] \[x+y=5\] ??(i) Also from \[\Delta \,OCD,\,{{x}^{2}}+{{y}^{2}}=13\] .....(ii) Solving equations (i) and (ii), we get \[x=3\] and \[y=2\] \[\therefore \] Diagonals are 6 and 4.You need to login to perform this action.
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