A) \[{{r}^{2}}=O{{P}^{2}}+AP\times CP\]
B) \[{{r}^{2}}=O{{P}^{2}}+AP\times PB\]
C) \[{{r}^{2}}=O{{P}^{2}}+PB\times PC\]
D) \[{{r}^{2}}=O{{P}^{2}}+P{{B}^{2}}\]
Correct Answer: B
Solution :
From right angled \[\Delta \,OPC,\] \[O{{C}^{2}}=C{{P}^{2}}+O{{P}^{2}}\] or \[{{r}^{2}}=C{{P}^{2}}+O{{P}^{2}}\] ?..(i) Also, \[CP\times PD=AP\times PB\] or \[C{{P}^{2}}=AP\times PB\] (since \[CP=PD\] From equation (i) \[{{r}^{2}}=O{{P}^{2}}+AP\times PB\]You need to login to perform this action.
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