9th Class Mathematics Geometry Question Bank Geometry

  • question_answer
    In a right-angled triangle \[ABC,\,\,\angle BCA=90{}^\circ \]. CD is perpendicular from C to AB. By using the concept of area or areas of triangles, which one of the following relationships holds good?

    A) \[\frac{1}{C{{D}^{2}}}=\frac{1}{B{{C}^{2}}}-\frac{1}{C{{A}^{2}}}\]

    B) \[\frac{1}{C{{D}^{2}}}=\frac{1}{A{{B}^{2}}}+\frac{1}{C{{A}^{2}}}\]

    C) \[\frac{1}{C{{D}^{2}}}=\frac{1}{A{{B}^{2}}}-\frac{1}{C{{A}^{2}}}\]

    D) \[\frac{1}{C{{D}^{2}}}=\frac{1}{B{{C}^{2}}}+\frac{1}{C{{A}^{2}}}\]

    Correct Answer: D

    Solution :

    Not available


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