A) \[45{}^\circ \]
B) \[60{}^\circ \]
C) \[22.5{}^\circ \]
D) \[12.5{}^\circ \]
Correct Answer: C
Solution :
\[\angle 1=\angle 2\] \[4x=60{}^\circ \Rightarrow x=15{}^\circ \] \[\angle 1=\angle 4\] (Opposite angles) \[4x=x+2y\] \[3x=2y\] \[y=\frac{3x}{2}=\frac{3\times 15{}^\circ }{2}=\frac{45{}^\circ }{2}=22.5{}^\circ \]You need to login to perform this action.
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