A) \[\angle ECD={{65}^{o}}\]
B) \[\angle ACB=\]
C) \[{{60}^{o}}\]
D) \[{{55}^{o}}\]
Correct Answer: A
Solution :
Clearly, if \[OL=OM\] then \[\Rightarrow \] (\[AB=CD\] angle at centre is twice the angle at remaining part of circumference.) \[AB=CD\]\[\Rightarrow \] \[\angle AOB=\angle COD\]\[\angle AOB=\angle COD\] .You need to login to perform this action.
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