A) \[{{90}^{o}}\]
B) \[\angle A=\angle B=\angle C=\angle D={{90}^{o}}\]
C) \[x<y\]
D) \[x>y\]
Correct Answer: C
Solution :
Let ABC be an equilateral \[{{105}^{o}}\] and \[{{85}^{o}}\]. Since, A ABD is a right angled \[{{60}^{o}}\]\[\angle BAC={{45}^{o}}\], right angle at D. \[\angle BED={{120}^{o}}\] \[\angle ABD\] (By Pythagorus theorem.) \[{{15}^{o}}\] \[{{30}^{o}}\] (\[\because BD=BD\]) \[\angle CAD={{40}^{o}}\] \[\angle BDC={{25}^{o}}\] \[\angle BDC\] (\[{{85}^{o}}\]\[{{120}^{o}}\]) \[{{115}^{o}}\] \[{{95}^{o}}\] \[\angle PAD={{30}^{o}}\] \[\angle CPA={{45}^{o}}\]You need to login to perform this action.
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