A) 3.6cm
B) 2.7cm
C) 1.8cm
D) 10.8cm
Correct Answer: C
Solution :
In \[{{115}^{o}}\] E is the mid-point of AD and \[\Delta ABC\] So, EF must bisect AG. \[DG||EF\] F is the midpoint of AG. So \[\Delta ABC\] In ABCF, D is the mid-point of BC and \[DE||BC\] So DG must bisect FC. \[EF||AD\] G is the mid-point of FC So \[ED||AC\] Thus, \[DA\bot AB,\] \[CB\bot AB\]You need to login to perform this action.
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