A) \[{{180}^{o}}\]
B) r
C) \[\angle R={{138}^{o}}\]
D) \[\angle PQS\]
Correct Answer: C
Solution :
Join AO. Let AO intersects the circle at X. Since, \[\Rightarrow \]. [Radius is perpendicular to the tangent at point of contact.] \[{{90}^{o}}\] \[\square ABCD\] \[\Rightarrow \] \[\angle 1=\angle 2=\angle 3=\angle 4={{90}^{o}}\] \[AB=CD\] \[AB||DC\]\[AD=BC\] \[AD||BC\]You need to login to perform this action.
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