A) \[{{40}^{o}}\]
B) \[{{60}^{o}}\]
C) \[{{90}^{o}}\]
D) \[{{30}^{o}}\]
Correct Answer: B
Solution :
\[ABCD\] \[\Rightarrow \] \[{{90}^{o}}\] is an equilateral triangle. So \[\square ABCD\], also \[\Rightarrow \]. \[\angle 1=\angle 2=\angle 3=\angle 4={{90}^{o}}\]\[AB=CD\].You need to login to perform this action.
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