A) \[180{}^\circ \]
B) \[210{}^\circ \]
C) \[150{}^\circ \]
D) \[90{}^\circ \]
Correct Answer: A
Solution :
In \[\Delta ABC\] \[\angle A+\angle B+\angle C=180{}^\circ \] \[30{}^\circ +x{}^\circ +120{}^\circ =180{}^\circ \] \[x=130{}^\circ \] \[x=y=30{}^\circ \] Now, in \[\Delta ADE\] \[30{}^\circ +y+z=180{}^\circ \] \[z=120{}^\circ \] \[\therefore \]\[x+y+z=30{}^\circ +30{}^\circ +120{}^\circ =180{}^\circ \]You need to login to perform this action.
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