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8th Class Mathematics Practical Geometry Question Bank Geometry

  • question_answer
    In the adjoining figure, a \[{{60}^{o}}\] has been given in which AD is its median, E is the mid-point of AD, BE produced meets AC at F and \[\angle CAD={{40}^{o}}\], meets AC at G. If AC = 5.4 cm then the length of AF is

    A) 3.6cm                         

    B) 2.7cm

    C) 1.8cm         

    D) 10.8cm

    Correct Answer: C

    Solution :

    In \[{{115}^{o}}\] E is the mid-point of AD and \[\Delta ABC\] So, EF must bisect AG. \[DG||EF\] F is the midpoint of AG. So     \[\Delta ABC\] In ABCF, D is the mid-point of BC and \[DE||BC\] So DG must bisect FC. \[EF||AD\] G is the mid-point of FC So  \[ED||AC\] Thus,   \[DA\bot AB,\] \[CB\bot AB\]             


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