A) \[\Delta XYZ\]
B) \[{{60}^{o}}\]
C) \[{{30}^{o}}\]
D) \[{{80}^{o}}\]
Correct Answer: B
Solution :
\[\therefore \] \[\frac{AB}{BC}=\frac{PQ}{QR}\] \[\angle 4=\angle 2\] \[\angle 6=\angle 3\] \[\angle 1=\angle 2\] \[\angle 3=\angle 5\] \[{{180}^{o}}\] \[\angle 1+\angle 3={{180}^{o}}\] \[\angle 5+\angle 2={{180}^{o}}\] Exterior angle is equal to the sum of opposite interior angles So, \[1||m||n\] \[\angle A,\angle B\] \[\angle C\] \[{{180}^{o}}\] \[\Rightarrow \] \[\angle 1+\angle 2+\angle 3={{180}^{o}}\]
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