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9th Class Mathematics Geometry Question Bank Geometry

  • question_answer
    In the given circle ABCD, O is the centre and \[\angle BDC\,=\,\,42{}^\circ .\]. The \[\angle ACB\] is equal to

    A) \[42{}^\circ \]

    B) \[45{}^\circ \]

    C) \[48{}^\circ \]

    D) \[60{}^\circ \]

    Correct Answer: A

    Solution :

     As the \[\angle BDC\] and \[\angle ACB\]are in the same segment, thus they are equal. But      \[\angle BDC={{42}^{o}}\]therefore \[\angle ACB={{42}^{o}}\]


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