A) \[40{}^\circ \]
B) \[60{}^\circ \]
C) \[80{}^\circ \]
D) \[120{}^\circ \]
Correct Answer: C
Solution :
Clearly, \[CP=CQ\] (Radii of circle) and \[CR=CP\] \[\therefore \] \[\angle CPQ={{25}^{o}}\] and \[\angle CPR={{15}^{o}}\] So that \[\angle QPR={{40}^{o}}\] Hence, \[\angle QCR=2\angle QPR\] \[=2\times {{40}^{o}}={{80}^{o}}\]You need to login to perform this action.
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