8th Class
Mathematics
Practical Geometry
Question Bank
Geometry
question_answer
The diagonals of a parallelogram ABCD intersect at O. If \[{{240}^{o}}\], then \[{{60}^{o}}\] is
A) \[{{120}^{o}}\]
B)\[{{180}^{o}}\]
C) \[\angle R={{138}^{o}}\]
D) \[{{90}^{o}}\]
Correct Answer:
D
Solution :
\[\Rightarrow \] or \[\angle 1+\angle 2+\angle 3={{180}^{o}}\] Alternate Method: In triangle, OAB, since sum of angles is\[\Rightarrow \], we have \[BD=CD\]