A) \[45{}^\circ \]
B) \[25{}^\circ \]
C) \[35{}^\circ \]
D) \[30{}^\circ \]
Correct Answer: B
Solution :
Since AB || CD \[\angle \,FCD=\angle \,ABF\] [alternate angles] = 45° In \[\Delta FCD,\] \[\angle \,FCD+\angle CDF+\angle CFD={{180}^{\text{o}}}\] [Angle sum property] \[{{45}^{\text{o}}}+\angle \,FDC+{{110}^{\text{o}}}\,={{180}^{\text{o}}}\] \[\angle \,FDC={{155}^{\text{o}}}={{180}^{\text{o}}}\] \[\angle \,FDC={{180}^{\text{o}\,}}-{{155}^{\text{o}}}\,={{25}^{\text{o}}}\]
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