A) \[CE||BA\]and \[\angle ECD={{65}^{o}}\]
B) \[\angle ACB=\]and \[{{60}^{o}}\]
C) \[{{55}^{o}}\]and \[{{70}^{o}}\]
D) \[{{90}^{o}}\]and\[l||m,\]
Correct Answer: C
Solution :
Let the major arc subtend \[x{}^\circ \]at centre. Since it is twice the minor arc, the minor arc subtends \[x+\frac{x}{2}={{120}^{o}}\] at centre. But \[\therefore \] \[\frac{AB}{BC}=\frac{PQ}{QR}\] \[\angle 4=\angle 2\] and \[\angle 6=\angle 3\]
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