A) \[30{}^\circ ,\text{ }30{}^\circ ,\text{ }120{}^\circ ,\text{ }180{}^\circ \]
B) \[60{}^\circ ,\text{ }60{}^\circ ,\text{ }120{}^\circ ,\text{ }120{}^\circ \]
C) \[60{}^\circ ,\text{ }90{}^\circ ,\text{ }90{}^\circ ,\text{ }120{}^\circ \]
D) \[30{}^\circ ,\text{ }60{}^\circ ,\text{ }90{}^\circ ,\text{ }180{}^\circ \]
Correct Answer: B
Solution :
\[\angle SOQ=\alpha \] then \[\angle POS=2\alpha \] \[\therefore \] \[\alpha +2\alpha ={{180}^{o}}\] \[\alpha ={{60}^{o}}\] Hence, angles are \[\alpha ,\alpha ,2\alpha \]and \[2\alpha \] i.e. \[{{60}^{o}},\text{ }{{60}^{o}},\text{ }{{120}^{o}}\]and \[{{120}^{o}}\].You need to login to perform this action.
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