A) \[DE||BC\]
B) \[y-3x=-9\]
C) \[\angle BAC\]
D) \[{{30}^{o}}\]
Correct Answer: D
Solution :
Since, \[\angle C\]\[{{180}^{o}}\] PQ is the diameter of circle, Join RQ. \[\Rightarrow \] (Angle in semi-circle) \[\angle 1+\angle 2+\angle 3={{180}^{o}}\] \[\Rightarrow \] But \[BD=CD\] \[\Rightarrow \] \[\frac{AO}{OD}=\frac{2}{1}\] (\[AO:OD=2:1\] \[\angle A,\angle B,\angle C\] is isosceles \[\angle D\]) \[{{360}^{o}}\] \[{{360}^{o}}\]
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