A) \[55{}^\circ \]
B) \[110{}^\circ \]
C) \[70{}^\circ \]
D) \[27.5{}^\circ \]
Correct Answer: D
Solution :
In \[\Delta DBA,\] \[DB=DA\] \[\Rightarrow \] \[\angle DBA=\angle BAD=35{}^\circ \] In\[\Delta BCD,\]\[DC=DB\Rightarrow \angle CBD=\angle BCD=2x\] In\[\Delta ABC,\angle A+\angle B+\angle C=180{}^\circ \] \[35{}^\circ +(35+2x)+2x=180{}^\circ \] \[4x=180{}^\circ -70{}^\circ =110{}^\circ \] \[x=\frac{110{}^\circ }{4}=27.5{}^\circ \]You need to login to perform this action.
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