A) \[225{}^\circ \]
B) \[90{}^\circ \]
C) \[180{}^\circ \]
D) \[170{}^\circ \]
Correct Answer: D
Solution :
Since PR || QS \[\angle MAB=\angle ADC\] (Corresponding angles) \[\angle \,ADQ+\angle ADC={{180}^{\text{o}}}\] (Linear pair) \[\angle \,ADC={{180}^{\text{o}}}\,-{{110}^{\text{o}}}={{70}^{\text{o}}}\] \[\angle \,={{70}^{\text{o}}}\] \[\angle \,ABC=\angle \,NBR\] (Vertically opposite angles) = 100° Since PR || QS, \[\angle \,BCS=\angle \,ABC\] (Alternate angles) \[\angle \,b={{100}^{\text{o}}}\] \[m\angle a+m\angle b={{70}^{\text{o}}}+{{100}^{\text{o}}}={{170}^{\text{o}}}\]You need to login to perform this action.
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