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8th Class Mathematics Practical Geometry Question Bank Geometry

  • question_answer
    O is the centre of a circle and if \[\angle A={{60}^{o}},\] then \[CE||BA\] is equal to

    A)  \[\angle ECD={{65}^{o}}\]                       

    B)  \[\angle ACB=\]

    C)  \[{{60}^{o}}\]                                

    D)  \[{{55}^{o}}\]

    Correct Answer: A

    Solution :

    Clearly, if \[OL=OM\] then \[\Rightarrow \] (\[AB=CD\] angle at centre is twice the angle at remaining part of circumference.) \[AB=CD\]\[\Rightarrow \] \[\angle AOB=\angle COD\]\[\angle AOB=\angle COD\] .


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