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9th Class Mathematics Geometry Question Bank Geometry

  • question_answer
    In quadrilateral ABCD, the sides and diagonals are related as

    A)  AB + BC + CD + DA > AC + BD  

    B)  AB + BC + CD + DA < AC + BD

    C)  AB + BC + CD + DA= AC + BD

    D) AB + BC + CD + DA > AC\[\Delta \]BD

    Correct Answer: A

    Solution :

                    \[(AD+AB)>BD\] \[(AB+AC)>AC\] \[(BC+CD)>BD\]                 and        \[(CD+AD)>AC\]                 \[\therefore \] \[2(AB+BC+CD+DA)>2(AC+BD)\]                 or \[(AB+BC+CD+DA)>(AC+BD)\]


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