A) 27
B) 24
C) 21
D) 18
Correct Answer: D
Solution :
In \[\Delta {{\,}^{S}}\,ACD\] and ACE. A is common to both and \[\angle D=\angle C\](because \[\angle D=\angle B\]and \[\angle B=\angle C\]) \[\therefore \] \[\Delta {{\,}^{S}}\,ACD\] and ACE are equiangular \[\therefore \] \[\frac{AC}{AE}=\frac{AD}{AC}\] or \[\frac{12}{8}=\frac{AD}{12}\] or \[8\,AD=12\times 12\] or \[AD=\frac{12\times 12}{8=18\,cm}\]You need to login to perform this action.
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