JEE Main & Advanced Physics Transmission of Heat Question Bank Graphical Questions

  • question_answer
    The graph. Shown in the adjacent diagram, represents the variation of temperature (T) of two bodies, x and y having same surface area, with time (t) due to the emission of radiation. Find the correct relation between the emissivity (e) and absorptivity (a) of the two bodies [IIT-JEE (Screening) 2003]

    A)            \[{{e}_{x}}>{{e}_{y}}\And \,\,\,{{a}_{x}}<{{a}_{y}}\]

    B)            \[{{e}_{x}}<{{e}_{y}}\And \,\,\,{{a}_{x}}>{{a}_{y}}\]

    C)            \[{{e}_{x}}>{{e}_{y}}\And \,\,\,{{a}_{x}}>{{a}_{y}}\]

    D)            \[{{e}_{x}}<{{e}_{y}}\And \,\,\,{{a}_{x}}<{{a}_{y}}\]

    Correct Answer: C

    Solution :

                       Rate of cooling \[\left( -\frac{dT}{dt} \right)\ \propto \] emissivity (e)                    From graph, \[{{\left( -\frac{dT}{dt} \right)}_{x}}>{{\left( -\frac{dT}{dt} \right)}_{y}}\] Þ \[{{e}_{x}}>{{e}_{y}}\]                    Further emissivity (e) µ Absorptive power  Þ \[{{a}_{x}}>{{a}_{y}}\]            (\[\because \] good absorbers are good emitters).


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