A) I, III
B) II, IV
C) II, III
D) I, IV
Correct Answer: A
Solution :
Potential energy is minimum (in this case zero) at mean position (x = 0) and maximum at extreme position \[(x=\pm A).\] At time t = 0, x = A, hence potential should be maximum. Therefore graph I is correct. Further in graph III. Potential energy is minimum at x = 0, hence this is also correct.You need to login to perform this action.
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