A) P
B) Q
C) R
D) S
Correct Answer: B
Solution :
At t = 0 and \[x=\frac{\pi }{2k}\]. The displacement \[y={{a}_{0}}\sin \,\left( \omega {{x}_{0}}-k\times \frac{\pi }{2x} \right)=-{{a}_{0}}\sin \frac{\pi }{2}=-{{a}_{0}}\] from graph. Point of maximum displacement (a0) in negative direction is Q.You need to login to perform this action.
You will be redirected in
3 sec