A) Spring did not obey Hooke's Law
B) Amplitude of the oscillations was too large
C) Clock used needed regulating
D) Mass of the pan was neglected
Correct Answer: D
Solution :
\[T=2\pi \sqrt{\frac{M}{K}}\]Þ \[{{T}^{2}}\propto M\] If we draw a graph between \[{{T}^{2}}\]and M then it will be straight line. and for M = 0, T2 = 0 i.e. the graph should pass through the origin. but from the it is not reflected it means the mass of pan was neglected.
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