A) 16 J
B) 32 J
C) 1.6 J
D) 8 J
Correct Answer: A
Solution :
Work done = Area under curve and displacement axis = Area of trapezium = \[\frac{1}{2}\]×(sum of two parallel lines) × distance between them = \[\frac{1}{2}(10+4)\times (2.5-0.5)\] = \[\frac{1}{2}14\times 2\]= 14 J As the area actually is not trapezium so work done will be more than 14 J i.e. approximately 16 J
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